Jonathan’s lunch account began with $50 and he spends $2.25 per day on his lunch. Nelson’s lunch account began with $13 and he spends $0.40 per day on his lunch. Which equation could be used to solve how many day, d, Jonathan and Nelson will have the same amount of money in their lunch accounts? Answer Choices-
50−2.25d=13−0.40d50 minus 2 point 2 5 d is equal to 13 minus 0 point 4 0 d

50+2.25d=13+0.40d50 plus 2 point 2 5 d is equal to 13 plus 0 point 4 0 d

50d−2.25= 13d−0.4050d−2.25= 13d−0.40

50d+2.25=13d+0.40

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500