What is the perimeter of a polygon with verticals at (-1, 3) , (-1, 6) , (2, 10) , (5, 6) , and (5, 3)

22 units

Step-by-step explanation:

The perimeter of a polygon is said to be the sum of the length of it's sides.

From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are

A = (−1, 3)

B = (−1, 6) ​

C = (2, 10)

D = (5, 6) ​​

E = (5, 3) ​

To find the distance between two points, we use the formula

d = √[(y2 - y1)² + (x2 - x1)²]

Between A and B, we have

d(ab) = √[(6 - 3)² + (-1 --1)²]

d(ab) = √(3²) + 0

d(ab) = √9 = 3

Between B and C, we have

d(bc) = √[(10 - 6)² + (2 --1)²]

d(bc) = √[4² + 3²]

d(bc) = √(16 + 9) = √25 = 5

Between C and D, we have

d(cd) = √[(6 - 10)² + (5 - 2)²]

d(cd) = √[(-4)² + 3²]

d(cd) = √(16 + 9) = √25 = 5

Between D and E, we have

d(de) = √[(3 - 6)² + (5 - 5)²]

d(de) = √(-3)² + 0

d(de) = √9 = 3

Between E and A, we have

d(ea) = √[(3 - 3)² + (5 --1)²]

d(ea) = √[0 + (6)²]

d(ea) = √36 = 6

The perimeter is given as

d(ab) + d(bc) + d(cd) + d(de) + d(ea) =

3 + 5 + 5 + 3 + 6 = 22 units

two? xd

step-by-step explanation: