The coordinates of the vertices of square ABCD are A(-2,-2),B(-2, 0), C(0, 0)andD(0, -2). Which of the following are the coordinates of the vertices of the transformed image using (2x, 3y)?
O A. A’ (4,6), B' (4,0),
C'(0, 0), and D'(0, 6)
OB. A' (0,1), B' (0,3),
C'' (2,3), and D' (2,1)
OC. A'(-4,-6), B' (-4,0),
C'(0, 0), and D' (0, -6)
O D. A' (-6,-4), B' (-6,0),
C'(0, 0), and D' (0, -4)
O

4

step-by-step explanation:

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1