Mathematics, 25.02.2021 20:50, robertrkumar1

Solve with subsitution
y-3x=2
y=-2x-8
show ur work HURRY PLSS

Answers: 3

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Answers

answered: anikabarnhart

y-3x=21

y=-2x-8 2

substituting value of y in equation 1

-2x-8-3x=2

-5x=2+8

x=10/-5=-2

substituting value of x in equation 1

y-3×(-2)=2

y+6=2

y=2-6=-4

x=-2

y=-4

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answered: kookycookiefanx

(-2, -4) or x = -2 y = -4

Step-by-step explanation:

Solve with subsitution

y-3x=2

y=-2x-8

1. Substitute -2x - 8 in for the y in y - 3x = 2 (-2x - 8) - 3x = 2

2. Solve for x. Combine like terms. -5x - 8 = 2

3. Solve the one step equation. +8 +8

-5x = 10

-5 -5

x = -2

4. Substitute the -2 in for x in either equation. y = -2x - 8

y = -2(-2) - 8

y = 4 - 8

y = -4

answered: Guest

step-by-step explanation:

you are throwing one dart

answered: Guest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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Solve with subsitution
y-3x=2
y=-2x-8
show ur work HURRY PLSS...