PLEASE HELP! ITS A DECENTLY EASY QUESTION BUT I CANT FIGURE IT OUT!

3,4 and 5 are correct☺

3,4,5

Step-by-step explanation:

To answer, we must go through all the expressions shown, solve them, and make sure that they are exactly like 3xy + 6yz.

1. We must distribute 3 to whatever is in the parentheses, but if you look, you can see that we have to multiply 3 by 6yz, which would come out to 18yz, and that is not in the original expression, so this one is FALSE

2. For this expression, we can rule it out because the first part of the expression would be 3xyz, and that is not a part of the original expression, this is one is FALSE

3. This expression, if you distribute the 3y, you get 3yx + 6zy, which is the same as the original expression, even if the variables are a bit jumbled, they all have the same value, so this one is TRUE

4. If you distribute y for this expression, you get y3x + y6z, which is the same as the original expression, because as I said before, the variables can be jumbled, but as long as all the values are there, we can safely say that this expression is TRUE

5. As you can see, this expression is the same as 4, so this one is also TRUE

Hope this helps :)

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer