Suppose that a polynomial has a zero at -5 with a multiplicity of 1, a zero at 2 with a multiplicity of 7, and a zero at -6 with a multiplicity of 3. Please help !

(A) Write a possible function in factored form that would have these zeros with their multiplicity. Answer here

(B) What is the degree of your polynomial function? Explain how you determined the degree. Answer here

(C) Write a second polynomial function having the same zeroes and multiplicity as stated above, but with a
different degree. Answer here

24+x=y

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

1 mph

step-by-step explanation:

if the question is asking how much does she drive per mile then,

13 / 13 = 1 mph