Jonathan is putting a border around a right triangle and needs to figure out the triangle's height. If the triangle has a base length of 4 cm and a total area of 24 cm², what is the height?

Step-by-step explanation:

formula to find area of a triangle:

A=1/2 × base × height(h)

insert the values into the formula:

24=1/2 × 4 × h

solve for h :

24=2h

24/2=h

h = 12 cm ( Ans )

the answer is a

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)