Solve
"7x^2+19x-6 = 0

Step-by-step explanation:

Given

7x² + 19x - 6 = 0

7x² + (21 - 2) x - 6 = 0

7x² + 21x - 2x - 6 = 0

7x( x + 3 ) - 2 ( x + 3 ) = 0

(x + 3 ) ( 7x - 2 ) = 0

Either

x + 3 = 0

x = - 3

Or,

7x - 2 = 0

7x = 2

x = 2 /7

So

x = - 3 and 2/7

Hope it will help :)

x= -3,/2/7

Step-by-step explanation:

split the second term in 7x^2 + 19x-6 into two terms 7x^2+21x-2x-6=0

Factor out common terms in the first two terms7x(x+3)-2(x+3)=0

(x+3)(7x-2)=0

Factor out the common term x+3 hope that help x= -3,/2/7

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150