Solve the simultaneous equations by substitution
2x + 5y = 26
X – y=6

2x+5y =26

X-y=6

These equations will Remain the same and will be categorized as expressions as unlike terms cannot be added.

2x+5y=26equ 1

x-y=6 equ 2

solution

from equation 2 we have,

x=6+y... equ 3

substituting x in equ 1 we have,

2x+5y=26

2(6+y)+5y=26

12+2y+5y=26

7y=14

y=2

substituting y in equ 3 we have,

x=6+y

x=6+2=8

y=2, x=8

x=4

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)