A person leaning off a cliff 230 meters above the ground shoots an object into the air with an initial vertical velocity of 30 meters per second. The equation h = -10t2 + 30t + 230 gives the height, h, of the object when it is in the air for t seconds. After how many seconds is the object at a height of 50 meters above the ground?

ou would have 12 of each

idk

step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5