Two brothers have ages that are consecutive odd integers. The product of their ages is 38 less than the older brother's age squared. What are the ages of the two brothers?

answer = the elder bother is 17 and the younger one is 15

constructive odd integers= 15 and 17

17×15= 255

255+38 = 293

Square root of 293 = 17

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )