Hiro rolls a fair pair of six-sided dice. The sample space of all possible outcomes is shown below. Let AAA be the event that the first die is one and BBB be the event that the sum of the dice is eight.
What is P(A\text{ or }B)P(A or B)P, left parenthesis, A, start text, space, o, r, space, end text, B, right parenthesis, the probability that the first die is one or the sum of the dice is eight?
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Step-by-step explanation:

Total outcomes for rolling a pair of six-sided dice n(S)= 6 x 6 =36

Let A be the event that the first die is one and B be the event that the sum of the dice is eight.

A = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)}

P(A)=

B= {(2,6), (6,2), (3,5), (5, 3), (4,4)}

P(B)=

A ∩ B = Ф

P(A ∩ B)=0

P(A or B)= P(A)+P(B)+P(A∩ B)

Hence, P(A or B) =

45

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;