Mathematics, 24.02.2021 20:40, tburlew01

Cameron claims y2=3x+3, y3=x+3, and y=x3+3 are all functions. Is Cameron correct? If not, determine Cameron's mistake, and state which of the relations are functions.(1 point) Cameron is incorrect; y=x3+3 is not a function because there are three values of x for at least one value of y. The relations y2=3x+3 and y3=x+3 are functions.

Cameron is incorrect; y2=3x+3 is not a function because there are two values of y for at least one value of x. The relations y3=x+3 and y=x3+3 are functions.

Cameron is correct.

Cameron is incorrect; y2=3x+3 and y3=x+3 are not functions because there are multiple values of y for at least one value of x in each relation. The relation y=x3+3 is a function. (my answer)

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Cameron claims y2=3x+3, y3=x+3, and y=x3+3 are all functions. Is Cameron correct? If not, determine...