The values of y for each value of x are:
![x = -3, y =2](/tpl/images/1139/4083/c3a6c.png)
![x = -2\: , y =-2](/tpl/images/1139/4083/85436.png)
.
![x = 0\: , y =-4](/tpl/images/1139/4083/4e8e8.png)
.
![x = 2\: , y =2](/tpl/images/1139/4083/e8be8.png)
![x = 3\: , y = 8](/tpl/images/1139/4083/d124e.png)
Step-by-step explanation:
We have all the values of x, they are from -3 to 3 passing for 0.
Now, we know that y is a quadratic function (y=x²+x+4)
Therefore, we just need to put each value of x into the quadratic equation to find each y value.
When:
![x = -3, y = (-3)^2+(-3)-4=2](/tpl/images/1139/4083/feb60.png)
![x = -3\: , y = 2](/tpl/images/1139/4083/09b01.png)
We can do this for all values of x, so we will have:
![x = -2\: , y = (-2)^2+(-2)-4=-2](/tpl/images/1139/4083/ad2fc.png)
.
![x = 0\: , y = (0)^2+(0)-4=-4](/tpl/images/1139/4083/b39f4.png)
.
![x = 2\: , y = (2)^2+(2)-4=2](/tpl/images/1139/4083/58300.png)
![x = 3\: , y = (3)^2+(3)-4=8](/tpl/images/1139/4083/c806c.png)
I hope it helps you!