A plane leaves an airport traveling at 400 mph in the direction N 45° E. A wind is blowing at 40 mph in the direction N 45° W. What is the ground speed of the plane? 400 mph
402 mph
429 mph
440 mph

402 mph

Step-by-step explanation:

Draw a right triangle with 400 and 40 as the two legs.

You know this is a right angle because 45 degrees NE is perpendicular to 45 degrees NW. (imagine a compass)

So, the two side lengths are 400 and 40

Using the Pythagorean theorem, (a^2 + b^2 = c^2) you can see that the answer is 401.995, or 402

B

Step-by-step explanation:

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )