A radioactive substance decays in such way that the amount of mass remaining after t days is given by the function
, where m (t) is measured in grams.
m(t) = 12e-0.0671
1. Find the mass at time t = 0.
2. How much of the mass remains after 30 days? (Round to
nearest tenth of a gram)

answer: that was hard but still working on it

step-by-step explanation:

idk do it yourself or ask somebody idk stop going online asking for

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2