Given w= sqrt 2(cos( pi/4) + i sin (pi/4)) and z = 2(cos (pi/2 ) + i sin(pi/2)),

what is w- z expressed in polar form?

A. sqrt2 (cos(pi/4) + i sin(pi/4))

B. sqrt2 (cos(3pi/4) + i sin(3pi/4))

C. sqrt2 (cos(5pi/4) + i sin(5pi/4))

D. sqrt2 (cos(7pi/4) i sin(7pi/4))

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.