Need help with this asap!

Step-by-step explanation:

step 1. m: m is the variable, 1 is the coefficient, 1 is the degree, constant is 0.

step 2. 3t^2 +4t - 6: t is the variable, 3 and 4 are the coefficients, 2 is the degree, -6 is the constant.

step 3. 2 - h: h is the variable, -1 is the coefficient, 1 is the degree (highest variable exponent), the constant is 2.

step 4. -7a^2: a is the variable, -7 is the coefficient (before the variable), 2 is the degree, the constant is 0.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.