A man invests 10000 for 3 years at a certain rate of interest, compounded annually. At the end of one year, it amounts to 11200. Calculate :
(i) the rate of interest per annum;
(ii) the interest accrued in the second year;
(ii) the amount at the end of the third year.​

Step-by-step explanation:

10000, After 1 year amount = 11200 so interest after 1 year = 1200

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%

Interest for the second year = 11200(1+12/100)1 - 11200 = 1344

after 3 years = 10000(1+12/100)3 = 14049.28

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!