Richard Hoskins was the leader of a 4-H club with 27 children. When he divided the club into groups of 5 to play a game, how many groups did he have? How many extra children were there?

5 groups

2 extra children

Step-by-step explanation:

The computation of a number of groups and number of extra children is shown below:

Given that

There is 27 children

And, this group would be divided into group 5

So,

As we know that 25 is easily divided by 5

So there are 5 groups

And, the extra children is

= 27 - 25

= 2 chidren

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

sure thing bud

hope this