Triangle ABC has vertices A(-5, -1), B(5, -1), and C(0, -4). Is it scalene, isosceles or equilateral

Isosceles Triangle

Step-by-step explanation:

Triangle ABC has vertices A(-5, -1), B(5, -1), and C(0, -4). Is it scalene, isosceles or equilateral?

We solve this question using vertices formula:

√(x2 - x1)² + (y2 - y1)² when given vertices: (x1, y1) and (x2 , y2)

For Side AB

A(-5, -1), B(5, -1)

AB = √(5 - (-5))² + (-1 -(-1))²

AB= √(5 + 5)² + (-1 + 1)²

AB = √10² + 0

AB = √100

AB = 10 units

For Side BC

B(5, -1), C(0, -4)

BC = √(0 - 5)² + (-4 -(-1))²

BC = √-5² + (-4 + 1)²

BC = √25 + -3²

BC = √25 + 9

BC = √34

For Side AC

A(-5, -1), C(0, -4).

AC = √(0 - (-5))² + (-4 - (- 1)²

AC = √5² + -3²

AC = √25 + 9

AC = √34

Therefore this triangle is an isosceles triangle because 2 of its sides (AC and BC ) are equal to one another

answer: b.

step-by-step explanation:

it is b. cause the equations are put in the right category