What are the dimensions of the fenced in area if he only has 320 yards and the length is 5 yards more than 5 times the width

Length = 134.16yds, width = 25.8yds

Step-by-step explanation:

Perimeter of the yard = 2(L+W)

L is the length

W is the width

If length is 5 yards more than 5 times the width, then;

L = 5W+5

Substitute

P = 2(5W+5+W)

P = 2(6W+5)

P = 12W+10

320 = 12W +10

12W = 320-10

12W = 310

W = 310/12

W = 25.8

Since L = 5W+5

L = 5(25.8)+5

L = 129.16+5

L = 134.16yds

Length = 134.16yds, width = 25.8yds

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.