Find the solutions of each equation on the interval [0, 2π)
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Answer/Step-by-step explanation:

Factor this. GCF=2

2(2cos2x+cos x-1)=0

2(2cos x -1)(cos x+1)=0 Set each factor equal to zero and solve

2cos x -1=0 Add 1 to both sides

2cos x =1 Divide by 2

cos x =1/2

x=π/3

x=5π/3

cos x+1=0 Subtract 1 from both sides

cos x=-1

x = π

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

idk

step-by-step explanation:

i don't know