Need asap
which ordered pair is the solution to the system of equations?
x+3y=12
-4x+3y=-3
a.
(0, 4)
b.
(6, 2)
c.
(3, 3)
d.
(0, −1)

The answer is c. you use substitution after you find the x, which is 3. To do less work, when u see the answer has an x value of 3, only answer choice c has a x value of 3, limiting it to only that answer.

The answer is (3,3). To solve this, first you write the system down. 
x+3y=12
-4x+3y=-3
                         Next, you eliminate y by multiplying the bottom equation by negative 1. 
x+3y=12
-1(-4x+3y=-3)

                         Then, your answer is:
                                   x+3y=12
                                   4x-3y+3
                         Next, you combine like terms. Your answer is:
                                   5x=15. (The y's cancel out, because 3 is the opposite of negative 3.)
                                  Divide both sides by 5, leaving you with x=3. 
                                  Lastly, you substitute x into the top equation. You get:
                                 3+3y=12. 
                               Subtract 3 from both sides, leaving you with 3y=9.
                                 Divide both sides by 3, so y=3. The final answer is (3,3).

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5

The first one is 2/3the second is 1/160the third is 4/125