2. The lengths of the sides of a triangle are 4cm, 5cm and 6cm. Find, in degrees to one decimal place, the size of the largest angle of the triangle.
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82.8 degrees.

Step-by-step explanation:

The largest angle is opposite the longest side.

So we find the angle opposite the 6cm line using The Cosine Rule:

6^2 = 4^2 + 5^2 - 2.4.5 cos A

cos A = (6^2 - 4^2 - 5^2) / (-2*4*5)

= -5/ -40

=  0.125.

So m angle A = 82.8 degrees.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)