Find the area of parallelogram ABCD given m∠A = 30° and the following measures. AD = in.; AB = 8 in. A= 32 in.²
32√3 in.²
16√3 in.²'

Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3

Angle A =30

To find the area of the parallelogram

We have area of parallelogram = base x height

Here base can be taken as side AB = 6 ft

Height = perpendicular distance of AB from vertex X

= AX sin A

= 3√3sin30

=1.5√3

Hence area =6(1.5√3)=9√3ft^2

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16√3 in.²'

Step-by-step explanation:

Hope this helps, sorry for answering late.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: