Does anyone know how to do this ?

9514 1404 393

  y = 21

Step-by-step explanation:

In straightforward fashion, we can find the midpoints of the two segments, and set the distance between them equal to 10.

  M = midpoint of AB

  M = (A+B)/2 = ((-1, 0) +(-3, 6))/2 = (-4, 6)/2 = (-2, 3)

  N = midpoint of CD

  N = (C+D)/2 = ((3, 1) +(5, y))/2 = (8, 1+y)/2 = (4, (1+y)/2)

Then the distance MN is given by the distance formula.

  |N-M| = 10 = √((4 -(-2))² +((1+y)/2 -3)²) . . . . . distance formula*

  100 = 36 +((1+y)/2 -3)² . . . . . square both sides

  64 = ((1 +y)/2 -3)² . . . . . . . . . subtract 36

  8 = (1 +y)/2 -3 . . . . . . . . . . . . (positive) square root

  11 = 1+y/2 . . . . . . . . add 3

  22 = 1+y . . . . . . . . . multiply by 2

  21 = y . . . . . . . . . . . subtract 1

* The distance formula is an application of the Pythagorean theorem. Basically, the differences of x- and y-coordinates are taken to be the legs of a right triangle. They length of the hypotenuse is the distance between the two points.

  d² = (x2 -x1)² +(y2 -y1)² . . . . . . . from the Pythagorean theorem

  d = √((x2 -x1)² +(y2 -y1)²) . . . . . the usual distance formula

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.