One number is four less than a second number. Four times the first is 14 more than 5 times the second. Find the numbers.

First number is 6

Second number is 2

Step-by-step explanation:

The trick is that we need to set up two equations. Nor simplicity's sake I'm going to say the first number is x and the second number is y.

First we know that the first number (x) is 4 less than the second number (y).

Less means subtraction.

x-4=y

Then we know that 4 times x is 14 more than 5 times the second. More is addition and times is multiplication.

4x=14+5y

Now we use substitution to find out what x (the first number) is, subbing x-4 in for y.

4x=14+5(x-4)

4x=14+5x-20

-x=-6

x=6

First number is 6

Lastly, we sub 6 back into one of the equations. It's easier to us the first equation.

x-4=y

6-4=y

2=y

The second number is 2

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

idk

step-by-step explanation:

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