How many liters of 70% acid solution must be mixed with a 15% acid solution to get 550L of a 60% acid solution

9514 1404 393

  450 L

Step-by-step explanation:

Let x represent the number of liters of 70% solution needed. Then the amount of 15% solution needed is (550-x), and the total amount of acid in the mixture is ...

  0.70x + 0.15(550-x) = 0.60(550)

  0.55x + 82.5 = 330 . . . . simplify

  0.55x = 247.5 . . . . . . . . . subtract 82.5

  x = 450 . . . . . . . . . . . divide by 0.55

450 liters of 70% acid solution must be used.

the size of the resulting matrix is 1-by-3.

step-by-step explanation:

the size of the two matrices given are as follows:

no .of rows of matrix 1 = 1

no .of columns of matrix 1 = 3

no .of rows of matrix 1 = 3

no .of columns of matrix 1 = 3

to find the size of the resulting matrix without actually solving the multiplication of the matrix, this is what you do:

if resulting matrix = matrix 1 * matrix 2

no. of rows of the resulting matrix = number of rows of matrix 1

no. of columns of resulting matrix = number of columns of matrix 2

note: the order of the matrices matter!