Option B has no solution.
Step-by-step explanation:
To get the answer, we will solve all the equations:
A.
![4(x+3)+ 2x = 6(x + 2)](/tpl/images/0213/5640/b7222.png)
![4x+12+2x=6x+12](/tpl/images/0213/5640/d71b1.png)
Combining the like terms, we get
=
......Infinite solution
B.
![5+2(3+ 2x)= x+ 3(x + 1)](/tpl/images/0213/5640/b5aed.png)
![5+6+4x=x+3x+3](/tpl/images/0213/5640/86c29.png)
=
= 11=3 ...... NO solution.
C.
![5(x+3)+x=4(x+ 3)+ 3](/tpl/images/0213/5640/2c912.png)
![5x+15+x=4x+12+3](/tpl/images/0213/5640/26387.png)
= ![6x+15=4x+15](/tpl/images/0213/5640/9e4ff.png)
x= 0
D.
![4+6(2+x)=2(3x+8)](/tpl/images/0213/5640/5b201.png)
![4+12+6x=6x+16](/tpl/images/0213/5640/a3b14.png)
=
.... Infinite solution
Therefore Option B has no solution.