31= -(1+p) +4CP+6)

Please help solve

p=4CP - 26

C= p/4P + 13/2P

P= P/4C +13/2C

Step-by-step explanation:

p=4(p+6)-32

Step-by-step explanation:

31=−1−p+4(P+6)

2 Add 11 to both sides.

31+1=-p+4(P+6)

31+1=−p+4(P+6)

3 Simplify 31+131+1 to 3232.

32=-p+4(P+6)

32=−p+4(P+6)

4 Regroup terms.

32=4(P+6)−p

5 Subtract 4(P+6)4(P+6) from both sides.

32-4(P+6)=-p

32−4(P+6)=−p

6 Multiply both sides by -1−1.

-32+4(P+6)=p

−32+4(P+6)=p

7 Regroup terms.

4(P+6)-32=p

4(P+6)−32=p

8 Switch sides.

p=4(P+6)-32

p=4(P+6)−32

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !