You select a family with three children. If M represents a male child and Frepresents a female child, the sample space for a family with three kids is {MMM, MMF, MFM, MFF, FMM, FMF, FFM, FFF). What is the probability, as a percent to the nearest tenth, of
selecting a family with at least one male child? Hint: "at least one" means one or more

y=mx+b is the final answer!   : )

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12

the bolded word " farsighted" could be replaced with visionary.