I need somebody to be with (i know its not a dating site and i know I'm gay and i should be ashamed cause I'm an i-d-i-o-t.) but I'm crying (insert crying sound here.)

You shouldn't be ashamed cuz ur gay, thats just who u are and people should accept that, so dont be ashamed of it... UwU

Step-by-step explanation:

no

Step-by-step explanation:

step-by-step explanation:

if x = 2 you have to find x to finish the problem

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.