A parabola has x-intercepts of (2, 0) and (-4, 0) and has a leading coefficient of 1. What is the equation of the parabola in standard form? *

9514 1404 393

  y = x^2 +2x -8

Step-by-step explanation:

For x-intercepts p and q, factors of the parabola's equation are (x-p) and (x-q). Since the leading coefficient is 1, those are the only factors.

  y = (x -2)(x -(-4))

  y = (x -2)(x +4) = x(x +4) -2(x +4) . . . . use the distributive property

  y = x^2 +4x -2x -8 . . . . use the distributive property again

  y = x^2 +2x -8 . . . . . . . .equation in standard form

answer: i'm not sure

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10