a tree is broken at a height of 6 cm from the ground and its top touches the ground at a distance of 8cm from the base of the tree . find the original height of the tree pls do to step to step explaination ​

I guess its 16

Step-by-step explanation:

Because

Hieght =6cm

Base = 8cm

Hypotenuse=?

by pythagoras formula = a^2+b^2=c^2

6 *6 + 8*8 =c^2

36 + 64 = c^2

100 =c^2

Root of 100 is 10

so the whole tree is = to 10 +6 =16

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.