Where did the 9/4 come from? y = x^2 + 3x + 5
= ( x^2+3x ) +5
= (x^2 +3x + 9/4 ) - 9/4 +5
= (x + 3/2)^2 +11/4

( I already asked this question but someone literally answered it with an 'f' so i couldn't get an answer in the end :/ )

Ok so this concept is kind of hard to explain, but basically the two equations are equal because you are adding 9/4 and then subtracting 9/4, so you just end up with 0. The reason you do that is so you can make the (x + 3/2)^2 part, which you wouldn't be able to do without the 9/4/

When changing something to Vertex form you have the, in this case, coefficient to 3x which is 3 then square it. So you half it to 3/2 then square the fraction which becomes 9/4. Because you are adding the 9/4 in order to make this a perfect square you have to subtract it on the outside too leaving you with the answer provided.

In short:

When changing to stand form you need to half and square the X term to get the x intercept.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a