2 cars c and d started to move to each other car c was 118 miles from Boston car d was 256 miles from Boston car c was going twice as fast as car d how. Far from Boston will these 2 cars meet

131.3 miles

Step-by-step explanation:

The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.

Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:

d₁ + d₂ = 374 miles       (1)

Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence

For car c:

2x = d₁/t

t = d₁ / 2x

For car d;

x = d₂/t

t = d₂/ x

Since it takes both cars the same time to meet at the same point, therefore:

d₁/2x = d₂ / x

d₁ = 2d₂

d₁ - 2d₂ = 0         (2)

Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles

Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles

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