3y-4=6-2y
How do I solve this

solve the 3y and 2y first

Step-by-step explanation:

y = 2.

Step-by-step explanation:

We need to have  y terms on one side of the equation and numbers on the other side:-

3y - 4 = 6 -  2y    

 Add 2y to both sides:              

3y + 2y - 4 = 6 - 2y + 2y

5y - 4 = 6    

Add 4 to both sides:                      

5y  - 4 + 4 = 6 + 4

5y = 10

y = 10/5

y = 2.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2