The driver of a car traveling at 60 ft/sec suddenly applies the brakes. the position of the car is s(t) = 60t − 1.5t2, t seconds after the driver applies the brakes. how many seconds after the driver applies the brakes does the car come to a stop?

- After 20 seconds the driver applied the brakes to stop the car.

Explanation:-

Given:- The position of the car

∴Speed of the car

When car stopped the speed of car=0

Therefore, after 20 seconds the driver applied the brakes to stop the car.

im trinna find out'

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this