A projectile is launched at an angle of 45 degrees with an initial speed of 32 feet per second. How far does the projectile travel?

As the first part comes to the rest means, then it will fall under gravity directly.

First of all maximum height,

H=

g

u²sin²θ

H=

2×10

400×(

2

1

)

H=10m.

As initially the full projectile was supposed to land at A but due to explosion first part land at A', so to make the centre of mass lies at A the second part should lie at B.

f they don't break (explode) range OA

OA=

g

u²sin2θ

OA=400×sin45×

10

2

y = x + 95

y = 42 + 95

y=137 mm hg

take it another