I really need help with this

A+6+A = 20

A = 7

Step-by-step explanation:

J = number of problems Juana completed

A = number of problems Andy completed

J+A=20

J = A + 6

Replace J with A+6 in the first equation

A+6+A = 20

2A +6 = 20

Subtract 6 from each side

2A +6-6 = 20-6

2A =14

Divide by 2

2A/2 = 14/2

A = 7

7

Step-by-step explanation:

set up your two equations.

j + a = 20. equation 1

j = a + 6. equation 2

since you know that j = a + 6, you can substitute a + 6 into the place of j. this is because you want to isolate a in order to find out how many problems andy completed.

j + a = 20

a + 6 + a = 20

now solve.

2a + 6 = 20

2a = 14

a = 7

andy has completed 7 problems. if juana completed 6 more than andy, then she has completed 13. 13 + 7 = 20.

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.