X, Y and Z form the vertices of a triangle with area 59.7cm2. If XZ = 21.5cm and XY = 13.5cm, work out the acute angle ∠YXZ. Round to 1 DP.

The acute angle ∠YXZ = 24.3°.

Step-by-step explanation:

If in triangle ABC, C is the angle included between sides a and b then

Area of triangle =

here, XZ = 21.5cm and XY = 13.5cm are sides that includes acute angle ∠YXZ..

Area of a triangle = 59.7cm²

then, as per given, we have

Hence, the acute angle ∠YXZ = 24.3°.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb