To solve the system of linear equations 3 x + 5 y = 2 and 6 x + 10 y = 8 by using the linear combination method, Laura correctly multiplied the first equation by –2 to get Negative 6 x minus 10 y = negative 4 and then correctly added the equations Negative 6 x minus 10 y = negative 4 and 6 x + 10 y = 8 to get 0 = 4. How many solutions are there to the system of equations? 0
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(01.03 mc) which of the following is a step in simplifying the expression x multiplied by y to the power of 2 over x to the power of negative 3 multiplied by y to the power of 3, the whole to the power of negative 4. select one: a. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 7 multiplied by y to the power of negative 1. b. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of 12 multiplied by y to the power of negative 12. c. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of negative 3 multiplied by y to the power of 3. d. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 3 multiplied by y to the power of 3.