A scuba diver wants to descend at an average rate of at least 7 feet per minute for 5 minutes. The table shows how many feet the scuba diver descends in the first 4 minutes. How many feet must the scuba diver descend in the fifth minute to meet the goal?

The scuba diver must descend 3 feet in the fifth minute to meet the goal.

Step-by-step explanation:

To find how many feet does the scuba diver need to descend to reach the goal of 35 feet in 5 minutes, we need to calculate how many feet he did descend on the first 4 minutes.

So, calculating we have:

First Minute = 9ft

Second Minute = 11ft

Third Minute = 5 ft

Fourth Minute = 7 ft

Total = 9 ft + 11ft + 5ft + 7ft = 32 ft

Goal = 35 ft

Needed = Goal - Total ( 4 minutes)

Needed = 35 ft - 32 ft = 3 ft

Hence, we can see that at the 4 minute, he has only descended 32ft. It means that he need to descend 3 feet more in the fifth minute.

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: