How do you write the equation in slope intercept form given (-7,7) and (0,0)?

y=-x

Step-by-step explanation:

y=mx+b

m:slope

b: y-intercept

The slope is how steep the line is. The formula to find the slope with 2 coordinate pairs is

for this, it would be:

so the slope is negative one, this can be written as -x

The y-intercept is the point where x is 0 (this is where it crosses the y-axis). In this situation the y-intercept is 0, so you don't have to write it

idk man good luck man

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )