61 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows:

Complete question :

61 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows:

Pairs of Shoes4__5__6__7 __8 __9 __10 __11

Frequency : _ 8 _ 8 __5 _ 5 _ 9 __11 __7 ___8

Mean = 7.64 ;

Median = 8

Q1 = 5

Q3 = 9

Atleast 10 pairs = 24.6

76% is equivalent to

Step-by-step explanation:

Round all your answers to 4 decimal places where possible.

10

The mean is:

Σfx /Σf

((8*4)+(5*8)+(6*5)+(7*5)+(8*9)+(9*11)+(10*7)+11*8)) ÷ (8+8+5+5+9+11+7+8) = 7.64

The median is:

0.5(n+1)th observation

n = frequency = 61

0.5(61 +1) = 1/2 * 62 = 31st observation

= 8

First quartile:

0.25(n+1)th observation

n = frequency = 61

0.25(61 +1) = 1/4 * 62 = 15.5

(15 + 16)th observation ÷ 2 = (5 + 5) / 2 = 5

The sample standard deviation is:

The third quartile is:

0.75(n+1)th observation

n = frequency = 61

0.75(61 +1) = 1/4 * 62 = 46.5

(46 + 47)th observation ÷ 2 = (5 + 5) / 2 = 9

What percent of the respondents have at least 10 pairs of Shoes? %

(7 + 8) / 61 = 15 / 61 = 0.246

76% of all respondents have fewer than how many pairs of Shoes?

(76 / 100) * 61

0.76 * 61

= 46.36

(46th + 47th)

(9 + 10) = 19 /2 = 9.5 = 10

here is the

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