Which is the approximate solution for the system of equations x + 5= 10 and 3x + y = 1?

The approximate solution is (-0.36, 2.08).

Given system of equations : x+5y=10 and 3x+y=1

Step-by-step explanation:

First solve the first equation for x:  x = 5.  Next, substitute this 5 for x in the second equation:  3(5) + y = 1, or 15 + y = 1, or y = -14.  The solution is (5, -14).

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x