Among two supplementary angles the measure of the larger angle is 400 more than the measure of the smaller. Find their measures.
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9514 1404 393

  70° and 110°

Step-by-step explanation:

The sum of angles is 180°; their difference is 40°. So, the larger is ...

  (180° +40°)/2 = 110°

The smaller is 180° -110° = 70°

The two angles are 70° and 110°.

Above, we have "cut to the chase." If you let the larger be 'a' and 's' and 'd' represent the sum and difference, you have ...

  a + (a-d) = s . . . . the sum of the larger and smaller angles

  2a = s+d . . . . . .  add d

  a = (s+d)/2 . . . . the relation we used.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°