Mathematics, 15.02.2021 14:00, elysalmeron05

Hi, I've tried approaching this question. Doe anyone know how to solve it? The first few powers of 9 are $9^{0}$ = 1, $9^{1}$ = 9, $9^{2}$ = 81, $9^{3}$ = 729. Prove by strong induction that $9^{n}$ ends in 1 (unit digits = 1) if n is even and ends in 9 if n is odd.

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Hi, I've tried approaching this question. Doe anyone know how to solve it? The first few powers of...