POPULATION In 2000, the world population was calculated to be 6,071,675,206. The world population increases at a rate of about 1.2% annually. Write a function that represents the world population y after x years.

A) y = 6,071,675,205(1.012)^x

B) y = 6,071,675,206(1.012)^x

C) y = 6,071,605,205(1.012)^x

D) y = 6,071,675,215(1.012)^x

PLEASE HELP!!

B) y = 6,071,675,206(1.012)^x

Step-by-step explanation:

It appears that this question asks for an exponential model that represents the population growth. I believe you could view the equation in the form y = (initial population)(rate)^x

Since the initial population is 6,071,675,206, you could substitute that in to get y = 6,071,675,206(rate)^x

Since your rate is increasing by 1.2% (0.012 in decimal form), just convert that to decimal form (knowing that 100% = 1.0, add 0.012 to get 1.012). Substitute that in to get y = 6,071,675,206(1.012)^x

Hope that helps. Feel free to let me know if it made sense.

the correct answer is option c.   3

step-by-step explanation:

points to remember

equation of the line with coordinates (x₁, y₁) and (x₂, y₂) is given by,

slope m = (y₂ - y₁)/(x₂ - x₁)

from the figure we can see a line with two coordinates given

to find the slope of given line

here   (x₁, y₁)   = (-1, -1 ) and (x₂, y₂) = (1, 5)

slope m = (y₂ - y₁)/(x₂ - x₁)

  = (5 - -1)/(1 - -1)

  = (5 + 1)/(1 + 1)

  = 6/2 = 3

therefore the correct answer is option c.   3